Bertrand's Box Paradox Calculator

Explore the counterintuitive nature of conditional probability

Bertrand's Box Paradox Calculator

This calculator demonstrates Bertrand's Box Paradox. Given three boxes:

  • Box 1: Contains two gold coins
  • Box 2: Contains one gold coin and one silver coin
  • Box 3: Contains two silver coins

If you randomly select a box and then randomly select a coin from that box, and the coin you selected is gold, what is the probability that the box you chose is Box 1 (the box with two gold coins)?

What is Bertrand's Box Paradox?

Bertrand's Box Paradox is a famous probability puzzle that demonstrates how our intuition about probability can sometimes lead us astray. The paradox involves three boxes:

  • Box 1: Contains two gold coins
  • Box 2: Contains one gold coin and one silver coin
  • Box 3: Contains two silver coins

The paradox arises when you randomly select a box, randomly draw one coin from it, and it turns out to be gold. Many people intuitively think the probability that you chose Box 1 (with two gold coins) is 2/3, but the correct answer is actually 1/3.

How Does It Work?

The problem follows these steps:

  1. You randomly select one of the three boxes
  2. You randomly draw one coin from the selected box
  3. You observe that the coin is gold
  4. You need to determine the probability that you selected Box 1 (the box with two gold coins)

The key to understanding this paradox is recognizing that this is a conditional probability problem and applying Bayes' Theorem correctly.

Common Misconceptions

The most common misconception is thinking that since we drew a gold coin, it must be more likely that we chose Box 1. The reasoning usually goes:

  • Box 1 has two gold coins, so it's more likely to be the source of our gold coin
  • Box 2 has only one gold coin, so it's less likely to be the source
  • Box 3 has no gold coins, so we can eliminate it
  • Therefore, it must be twice as likely to be Box 1 than Box 2 (leading to the incorrect 2/3 probability)

This reasoning is flawed because it doesn't properly account for the conditional probabilities involved.

Mathematical Explanation

Let's solve this using Bayes' Theorem:

Prior Probabilities:

  • P(Box 1) = 1/3
  • P(Box 2) = 1/3
  • P(Box 3) = 1/3

Likelihoods:

  • P(Gold | Box 1) = 1 (both coins are gold)
  • P(Gold | Box 2) = 1/2 (one of two coins is gold)
  • P(Gold | Box 3) = 0 (no gold coins)

Using Bayes' Theorem:

P(Box 1 | Gold) = P(Gold | Box 1) × P(Box 1) / P(Gold)

Where P(Gold) = 1 × 1/3 + 1/2 × 1/3 + 0 × 1/3 = 1/2

Therefore: P(Box 1 | Gold) = (1 × 1/3) / (1/2) = 1/3

Real-World Applications

Understanding Bertrand's Box Paradox has important implications for:

  • Medical Diagnosis: Understanding how test results affect the probability of having a condition
  • Quality Control: Interpreting sampling results in manufacturing
  • Scientific Research: Avoiding bias in experimental design and data interpretation
  • Decision Making: Recognizing when intuition about probabilities might be misleading
  • Risk Assessment: Properly evaluating conditional probabilities in risk scenarios